PRINCIPLE AND PROCEDURE OF DIALYSIS

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    • #8317
      Ghazanfar Abbas
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      How do you calculate UF rate from KUF?
      If one needs to remove 2 kg during a period of 4 hours
      1- Add the volume of saline that will be given at the end of dialysis (usually 300 ml) and the amount of ingested fluid during dialysis (e.g., 100ml).
      2- This means that 2.4 L will have to be removed during 4 hours dialysis i.e.2.4 X 1000 /4 = 600 ml/hour.
      3- When using a dialyzer with KUF value of 4.0 ml/hour, the TMP will need to be set at 600/4 =150 mm Hg. N.B. (If the dialyzer KUF

    • #8782
      Miller
      Participant

      In medicine, dialysis (from Greek διάλυσις, diàlysis,, “loosening or splitting”) is the process of removing excess water, solutes, and toxins from the blood in people whose kidneys can no longer perform these functions naturally. This is referred to as renal replacement therapy.

      Dialysis is used in patients with rapidly developing loss of kidney function, called acute kidney injury (previously called acute renal failure), or slowly worsening kidney function, called Stage 5 chronic kidney disease, (previously called chronic kidney failure and end-stage renal disease and end-stage kidney disease).

      Dialysis is used as a temporary measure in either acute kidney injury or in those awaiting kidney transplant and as a permanent measure in those for whom a transplant is not indicated or not possible.[1]

      In the United Kingdom and the United States, dialysis is paid for by the government for those that are eligible. The first successful dialysis was performed in 1943.

      In research laboratories, dialysis technique can also be used to separate molecules based on their size. Additionally, it can be used to balance buffer between a sample and the solution “dialysis bath” or “dialysate”[2] that the sample is in. For dialysis in a laboratory, a tubular semipermeable membrane made of cellulose acetate or nitrocellulose is used.[3] Pore size is varied according to the size separation required with larger pore sizes allowing larger molecules to pass through the membrane. Solvents, ions and buffer can diffuse easily across the semipermeable membrane, but larger molecules are unable to pass through the pores. This can be used to purify proteins of interest from a complex mixture by removing smaller proteins and molecules.

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